4x^2+8x-5 how to factorise iy
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Answered by
2
Answer:
....Hope it helps buddy...
Step-by-step explanation:
4x²-8x-5 = 0
4x²+10x- 2x-5 = 0
2x(2x+5) - 1(2x+5)
(2x-1)(2x+5)=0
Answered by
2
Step-by-step explanation:
4x^2+8x-5=0
4x^2-2x+10x-5=0
2x(2x-1)+5(2x-1)=0
(2x-1)(2x+5)=0
2x-1=0 ,2x+5=0
2x=1,2x=-5
x=1/2,x=-5/2
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