Question

4x^2+9x-1=0
quadratic equation​

Answer 1

Answer:

a=4; b=9; c=(-1)

by Quadratic formula,

x = -b±√b^2 - 4ac/2a

= -9±√81 -(-16)/2(4)

= -9±√81+16/8

= -9±√97/8

Therefore, x = 1/8(-9-√97) or x = 1/8(-9+√97).

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Answer 2

Answer:

Hi !!

Step-by-step explanation:

$4x^{2} +16x-25x-100=0 \\4x(x+4)-25(x+4)=0\\(x+4)(4x-25)=0\\x+4=0 (or) 4x-25=0\\x=-4 (or) x=\frac{25}{4}\\Solution Set =-4,\frac{25}{4}$

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