Question

4x^2+9y^2=16xy then show that
2log(2x- 3y) = 2log2+log x+ logy

please answer this ​

Answer 1

Step-by-step explanation:

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Answer 2

Given

4x^2+9y^2=16xy

LHS

2log(2x-3y)=log (2x-3y)^2

=log(4x^2+9y^2--12xy)

=log (16xy-12xy)

=log4xy

=log 4+log x+log y

=2log 2+log x+log y

=RHS