Question

4x^2+kx+5 is divisible by x+1 the same expression is also divisible by​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

first we need to find the value of k

so,

x + 1 = 0

x = -1

f(x)= $4x^{2} + kx + 5$

f(-1) = 4$(-1)^{2}$ + k × -1 + 5

f(-1) = 4 -1K +5

f(-1) = 9-1K

∵ the equation is divisible by x+1

∴ f(-1) = 0

∴ 0=9-K

k=9

∴ f(x) = $4x^{2} + 9x + 5$

to find another factor,

factors of 5 = ±1 , ±5

f(1) = $4(1^{2} )$ + 9 × 1 + 5

f(1) = 4+9+5

equation remainder ≠ 0

next ,

f(-5) = $4(-5^{2} )$ + 9×-5 + 5

f(-5)= 4×25 - 45 + 5

f(-5) = 105 - 45 ≠ 0

hence x+1 is the only factor

if u want u can try like me above but x+1 is the only factor

this is ur answer please mark as brainliest