Math, asked by jasonjoshi8204, 8 months ago

4x^2-kx+9=0 find the value of k

Answers

Answered by dsdrivingsimulator
1

Answer:

4x^2+9

k= ______

x

Step-by-step explanation:

If x =1 then k=13

If x =2 then k=25/2

and so on....

Answered by Anonymous
3

HERE IS YOUR ANSWER MATE.....;

LET ASSUME D =0

SO,

b {}^{2}  - 4ac = 0

( - k) {}^{2}  - 4 \times 4  \times 9 = 0

k {}^{2}  - 144 = 0

k \:  =  \sqrt{144}

k = 12

HOPE IT'S HELPFUL.....:-)

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