Question

4x^2+kx+9=0 find the value of k so that it has real roots

Answer 1

Subtract $-4x^2$ to both sides

kx + 9 = $-4x^2$

Subtract both sides by -9

kx =  $-4x^2-9$

Divide both sides by x

$\frac{-4x^2-9}{x}$

Answer

$k=\frac{-4x^2-9}{x}$