Question

4x^2-(p-2) x+1. It has equal roots and solve the quadratic equation for p

Answer 1

Hi ,

Compare 4x² - ( p - 2 )x + 1 = 0 with

ax² + bx + c = 0 ,

we get ,

a = 4 ,

b = - ( p - 2 ) ,

c = 1 ,

It is given that roots are equal.

discreaminant ( D ) = 0

b² - 4ac = 0

[ - ( p - 2 ) ]² - 4 × 4 × 1 = 0

( p - 2 )² = 16

p - 2 = ± √16

p - 2 = ± 4

p = 2 ± 4

p = 2 + 4 or p = 2 - 4

p = 6 or p = -2

I hope this helps you.

: )

Answer 2

Hi,

Pleasesee the attached file!



Thanks