Question

4x 2 +y 2 +14x-7y-4xy+12 Factorise it.

Answer 1

$4x^2 +y^2+14x+-7y-4xy+12$

$= (2x-y)^2 - 7(2x - y) + 12$

[tex]Let 2x -y = a a^2 - 7a + 12 a + b = -7 ab = 12 a = -4 b= -3 Hence the equation  [/tex]

$Substitute a=- (2x - y - 4)(2x - y -3) Hence factored$

Answer 2

Answer:

$4x^2+y^2+14x-7y-4xy+12=(2x-y+4)(2x-y+3)$

Step-by-step explanation:

Given : Expression $4x^2+y^2+14x-7y-4xy+12$

To find : Factories the expression ?

Solution :

To factor the term we have to take common terms and arrange them in orders,

$4x^2+y^2+14x-7y-4xy+12$

Make the square term,

$=(2x)^2+(y)^2+14x-7y-2(2)xy+12$

$=(2x-y)^2+14x-7y+12$

$=(2x-y)^2+7(2x-y)+12$

Let 2x-y=a,

So, $=a^2+7a+12$

Factories by middle term split,

$=a^2+4a+3a+12$

$=a(a+4)+3(a+4)$

$=(a+4)(a+3)$

Substitute the value of a,

$=(2x-y+4)(2x-y+3)$

Therefore, $4x^2+y^2+14x-7y-4xy+12=(2x-y+4)(2x-y+3)$