Question

4x^2-y^2/25 algebric Identity​

Answer 1

Answer:

Q. Factorize 25x²/4 - y²/9

Solution- We can write 25x²/4 - y²/9 as (5x/2)²- (y/3)²

[We need to convert the 2 terms in the form of 2 whole squares so that we can apply the suitable algebraic identity.]

By using the algebraic identity a²-b²= (a+b) (a-b)

where a= 5x/2 and b= y/3

⇒ (5x/2+ y/3) (5x/2- y/3)

∴ 25x²/4 - y²/9=

Step-by-step explanation:

#Hope you have satisfied with this answer.

Answer 2

Answer:

Q. Factorize 25x²/4 - y²/9

Q. Factorize 25x²/4 - y²/9Solution- We can write 25x²/4 - y²/9 as (5x/2)²- (y/3)²

Q. Factorize 25x²/4 - y²/9Solution- We can write 25x²/4 - y²/9 as (5x/2)²- (y/3)²[We need to convert the 2 terms in the form of 2 whole squares so that we can apply the suitable algebraic identity.]

Q. Factorize 25x²/4 - y²/9Solution- We can write 25x²/4 - y²/9 as (5x/2)²- (y/3)²[We need to convert the 2 terms in the form of 2 whole squares so that we can apply the suitable algebraic identity.]By using the algebraic identity a²-b²= (a+b) (a-b)

Q. Factorize 25x²/4 - y²/9Solution- We can write 25x²/4 - y²/9 as (5x/2)²- (y/3)²[We need to convert the 2 terms in the form of 2 whole squares so that we can apply the suitable algebraic identity.]By using the algebraic identity a²-b²= (a+b) (a-b)where a= 5x/2 and b= y/3

Q. Factorize 25x²/4 - y²/9Solution- We can write 25x²/4 - y²/9 as (5x/2)²- (y/3)²[We need to convert the 2 terms in the form of 2 whole squares so that we can apply the suitable algebraic identity.]By using the algebraic identity a²-b²= (a+b) (a-b)where a= 5x/2 and b= y/3⇒ (5x/2+ y/3) (5x/2- y/3)

Q. Factorize 25x²/4 - y²/9Solution- We can write 25x²/4 - y²/9 as (5x/2)²- (y/3)²[We need to convert the 2 terms in the form of 2 whole squares so that we can apply the suitable algebraic identity.]By using the algebraic identity a²-b²= (a+b) (a-b)where a= 5x/2 and b= y/3⇒ (5x/2+ y/3) (5x/2- y/3)∴ 25x²/4 - y²/9=

Step-by-step explanation:

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