4x+2y-2=0; 3x+7y-6=0 in standard form
Answers
(i)The equation is 3x+2y−12=0
It can be written as
3x+2y=12
12
3x
+
12
2y
=1
i.e;
4
x
+
6
y
=1
This equation is of the form
a
x
+
b
y
=1,where a=4 and b=6.
Therefore equation (1) is in the intercept form,where the intercepts on the x and y axes are 4 and 6 respectively.
(ii)The given equation is 4x−3y=6
It can be written as
6
4x
−
6
3y
=1
3
2x
−
2
y
=1
i.e;
{
2
3
}
x
+
(−2)
y
=1
This equation is of the form
a
x
+
b
y
=1, where a=
2
3
and b=−2
Therefore equation (2) is in the intercept form,where the intercepts on the x and y axes are
2
3
and −2 respectively.
(iii)The given equation is 3y+2=0
It can be written as
3y=−2
i.e;
{−
3
2
}
y
=1
This equation is of the form
a
x
+
b
y
=1, where a=∞ and b=−
3
2
Therefore, equation (3) is in the intercept form, where the intercept on the y-axis is −
3
2
and it has no intercept on the x-axis