Question

4x^2y^2-4xyz+z^2 factorisation​

Answer 1

Answer:

$(2xy - z)^{2}$

Step-by-step explanation:

$4 {x}^{2} {y}^{2} - 4xyz + {z}^{2} \\ = (2xy)^{2} - 2 \times 2xy \times z + (z)^{2} \\ = (2xy - z) ^{2} (using (\: a - b) ^{2} = {a -}^{2} - 2ab + {b}^{2}$