Math, asked by rrudrukumbar, 15 days ago

4x -2y-4=0. 4x-4y-5=0 please send this answer I substitution method of pair of lenear equation plssssss SUBSTITUTION METHOD​

Answers

Answered by Adarshwalmiki
3

Answer:

4x-2y-4 =0

=4x-2y=4------(1)

4x-4y-5=0

=4x-4y=5------(2).

multiplying equation 1 by 2

=8x-4y=8-------(3)

substracting equation (2) by (3)

8x-4y=8

4x-4y=5

- + -

----------------

4x. =3

=x=4/3

substitution x=4/3 in equation 1

= 4x-2y=4

=4[4/3]-2y=4

=16-2y=4----------[by taking LCM]

=2y=4-16

=2y= -12

=y= -6

(x,y)= (4/3,-6)

Step-by-step explanation:

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