Question

4x-2y=4; -3x+3y=6 solve by elimination method

Answer 1

Answer:

multiply 1st equation by -3

then, -3(4x-2y=4)

= -12x+6y=-12

now 2nd equation = -3x+3y =6

multiply it by 4

4(-3x+3y = 6)

-12x +12y=24

subtract 1 from 2

then, -12x +6y =-12

-12x+12y=24. ( change sign)

+ - -

= -6y = -36

y = 36/6 ( - canceled)

y= 6

put value of y in 1

-12x+6y = -12

-12x+6(6)=-12

-12x+36=-12

-12x= -12/36

-12x= -1/3

x= -1/3( -12)

x=4

Answer 2

Answer:

Answer:

multiply 1st equation by -3

then, -3(4x-2y=4)

= -12x+6y=-12

now 2nd equation = -3x+3y =6

multiply it by 4

4(-3x+3y = 6)

-12x +12y=24

subtract 1 from 2

then, -12x +6y =-12

-12x+12y=24. ( change sign)

+ - -

= -6y = -36

y = 36/6 ( - canceled)

y= 6

put value of y in 1

-12x+6y = -12

-12x+6(6)=-12

-12x+36=-12

-12x= -12/36

-12x= -1/3

x= -1/3( -12)

x=4