Question

) (4x’ + 2y - 6xy) * (x’ – 3y’ + 2xy)​

Answer 1

Step-by-step explanation:

1

:

Equation at the end of step 1

(((4 • (x2)) • y) - (2•3xy2)) - 8xy

STEP

2

:

Equation at the end of step

2

:

((22x2 • y) - (2•3xy2)) - 8xy

STEP

3

:

STEP

4

:

Pulling out like terms

4.1 Pull out like factors :

4x2y - 6xy2 - 8xy = 2xy • (2x - 3y - 4)

Final result :

2xy • (2x - 3y - 4)

Answer 2

Answer:

= 4x(x-3y+2xy)+2y(x-3y+2xy)-6xy(x-3y+2xy)

= (4x^2-12xy+8yx^2)+(2xy-6y^2+4xy^2)-6yx^2+18xy^2-12x^2y^2

= -12x^2y^2+2yx^2+22xy^2-10xy+4x^2-6y^2

= 2xy(-6xy+x+11y-5)+4x^2-6y^2

= 2xy(x-6xy+11y-5)+4x^2-6y^2

hope it will help you