Question

4X^2Y(Z-1)/A+B-3C WHEN X=2,Y=-1,Z=3,A=0,B=4 AND C=1/3

Answer 1

Answer:

$\frac{ {4x}^{2y(z - 1)} }{a + b - 3c} \\ = \frac{ {4(2)}^{2( - 1)(3 - 1)} }{0 + 4 - 3( \frac{1}{3})} \\ = \frac{ {8}^{( - 2)(2)} }{4 - 1} \\ = \frac{ {8}^{ - 4} }{3} \\ = \frac{{4096}^{ - 1} }{3} \\ = \frac{1}{4096 \times 3} \\ = \frac{1}{12288}$