4x^3-124x+120 factorise it .I will chose the answer brainliest
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4x³-124x+120
[ First you need to take a common so, here is
trick . What would. we put in instead of x to
get 4x³-124x+120 is zero like 4(1)³-124(1)+120 =
0 so take common (x-1) then, (x-1) (?) = 4x³-124x
+120 ? = 4x³-124x+120/(x-1) simply it you will
get Quotient then write like this which was in below ]
= (x-1) [(4x²+4x-120)]
= (x-1) [(4x²+24x-20x-120)]
= (x-1) [(4x(x+6)-20(x+6)]
= (x-1)(4x-20)(x+6)
[ First you need to take a common so, here is
trick . What would. we put in instead of x to
get 4x³-124x+120 is zero like 4(1)³-124(1)+120 =
0 so take common (x-1) then, (x-1) (?) = 4x³-124x
+120 ? = 4x³-124x+120/(x-1) simply it you will
get Quotient then write like this which was in below ]
= (x-1) [(4x²+4x-120)]
= (x-1) [(4x²+24x-20x-120)]
= (x-1) [(4x(x+6)-20(x+6)]
= (x-1)(4x-20)(x+6)
atulam:
bro plz solve the upper question also
i meant to say x-1 multiplied by any polynomial equal to p(x)×any polynomials
i am asking the question again plz solve it
ok
i have asked
ok wait I solve it
i got it bro
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