Question

4x + 3/2 = 1x/2 - 5 solve​

Answer 1

Answer:

Given,

4x + $\sf\frac{3}{2}$ = $\sf\frac{x}{2}$ - 5

To Find :-

Value of 'x'

Solution :-

4x + $\sf\frac{3}{2}$ = $\sf\frac{x}{2}$ - 5

Transposing all variable terms to Left side and all constant terms to Right side.

4x - $\sf\frac{x}{2}$ = -5 - $\sf\frac{3}{2}$

L.C.M of 1,2 = 2

$\sf\frac{4x(2)-x}{2}$ = $\sf\frac{-5(2)-3}{2}$

$\sf\frac{8x-x}{2}$ = $\sf\frac{-10-3}{2}$

$\sf\frac{7x}{2}$ = $\sf\frac{-13}{2}$

7x = 2 × $\sf\frac{-13}{2}$

7x = -13

x = $\sf\frac{-13}{7}$