Question

(4x-3)^2-2(x+3)=0






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Answer 1

Answer:

Here, we have

⇒ 4/x - 3 = 5/2x + 3

⇒ 4 - 3x/x = 5/2x + 3

⇒ (4 - 3x) (2x + 3) = 5x

⇒ 12 - x - 6x² = 5x

⇒ 6x² + x - 12 = 0

Dividing eq by 6, we get

⇒ x² + x - 2 = 0

By using factorization method, we get

⇒ x² + x - 2 = 0

⇒ x² + 2x - x - 2 = 0

⇒ x(x + 2) - 1(x + 2) = 0

⇒ (x + 2) (x - 1)

⇒ x + 2 = 0 or x - 1 = 0

⇒ x = - 2, 1 (As x can't be negative)

⇒ x = 1

But here, x = - 2, 1

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