Question

(4x-3)²-2(x+3)=0
solve this by Sridhara Acharyyas formula ​

Answer 1

$(4x-3)^2-2(x+3)\\\\16x^2+9-24x-2x-6\\\\16x^2-26x-3$

$\frac{-b-\sqrt{b^2-4ac}}{2a}\\or\\\frac{-b-\sqrt{b^2+4ac}}{2a}$

$Thus, \\\frac{26-\sqrt{676+192}}{32}\\\\\frac{26-\sqrt{868}}{32}\\\\\frac{13-\sqrt{217}}{16}$

And, the other root will be,

$\frac{13+\sqrt{217}}{16}$