Question

√4x-3 +√2x+3 = 6 plz sove this . this question from chapter quadratic equation class 10 answer is 3.​

Answer 1

Answer=》

√(4x-3) +√(2x+3) = 6

Step  1  :

√(4x - 3) = - √(2x + 3) + 6

Step  2  :

Eliminate the radical on the left hand side :

(√4x-3)² = (-√(2x+3)+6)²

4x - 3 = 2x + 3 + 36 - 12√2x + 3

12√2x+3 = -4x+3+2x+3+36

12√2x+3 = -2x+42

Step  3 :

Eliminate the radical on the left hand side :

(12√2x+3)² = (-2x+42)²

288x+432 = 4x²-168x+1764

4x²  - 456x  + 1332 = 0

x = 111, 3

Now check the solutions are correct

Step  4 :

√(4x-3) = -√(2x+3)+6

x= 111

√[4*(111)- 3] = -√[2*(111)+3]+6

√(444- 3) = -√(222+ 3 )+ 6

√441 = -15 + 6

 21 ≠ -9

So x = 111 will not work

Step  5  :

Check whether x=3 is correct

√4x-3 = -√2x+3+6

√4*(3)-3 = -√2*(3)+3+6

√9 = - 3 + 6

3 = 3

∴  x = 3

Answer 2

Answer:

$\sqrt{(4x - 3)} + \sqrt{2x + 3} = 6 \\ (4x - 3) \: \: + \: (2x + ) = 6 \\ 4x - 3 \: \: + 2x + 3 = 6 \\ 1x + 5x \\ = > answer \: is \: 6$

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