Question

[4x]^3=4^3^3 find x and solve

Answer 1

$4x−49−43<x</p><p></p><p>1216x−27−9<x</p><p></p><p>16x−36<12x</p><p></p><p>16x−12x<36</p><p></p><p>4x<36</p><p></p><p>x<436</p><p></p><p>or x<9 ....(3)</p><p></p><p>Now, solving inequality (2)</p><p></p><p>614x−2−7x−2>x</p><p></p><p>67x−4>x</p><p></p><p>7x−4>6x</p><p></p><p>7x−6x>4</p><p></p><p>x>4 ....(4)</p><p></p><p>$

Answer 2

Step-by-step explanation:

ANSWER

2x+1

4x−3

−10(

4x−3

2x+1

)=3 x



=

2

−1

,

4

3

On solving this we get

(2x+1)(4x−3)

(4x−3)

2

−10(2x+1)

2

=3

16x

2

+9−24x−40x

2

−10−40x=3(8x

2

−2x−3)

16x

2

−40x

2

−24x

2

−24x−40x+6x+9−10+9=0

−48x

2

−58x+8=0

48x

2

+58x−8=0

⇒48x

2

+58x−8=0 On dividing by 2

24x

2

+29x−4=0

x=

48

−29±

1225

=

48

−29±35

x=

48

6

,

48

−64

Hence values of x are (

8

1

,

3

−2

).