Math, asked by bushraf339gmailcom, 4 months ago

(4x-3)square -2(x+3)=0​

Answers

Answered by nishasharma50
0

Answer:

(4x-3)^2 -2(x+3)=0

(4x-3) (4x+3) -2(x+3)=0

(4x)^2 -(3)^2 -2(x+3)=0

16x^2 - 9 - 2(x+3)=0

16x^2 -9 -2x - 6 = 0

16 x^2 -9 - 2x = 0 + 6

16 x^2 square - 9 - 2 X = 6

16 x^2 - 2 x = 6 + 9

14x = 15

x = 14/15

x = 7/5

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