(4x-3)(x+2)-(3x-5)(-x-9)
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Answered by
6
Step-by-step explanation:
(4x-3)(x+2)-(3x-5)(-x-9)
= (4x² - 3x + 8x - 6) - (-3x² + 5x - 27x + 45)
= 4x² + 5x - 6 + 3x² - 22x + 45
= 7x² - 17x + 39
{splitting the middle term into the product of the 1st and the 3rd term,i.e., 39*7 = 273}
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Answered by
1
Answer:
(4x-3 × x-2 ) - (-3x-5 × -x-9) you can write as
=[ (4x-3 × x) +(4x-3 × -2) ] - (-3x -5 × -x-9)
= (4x² - 3x) + (-8x+5) - [ (3x-5 × -x) - (3x-5 × -9) ]
=(4x² - 3x) + (-8x+5) - (3x²+5x) - (27x +45)
=4x² -3x -8x +5 - 3x² + 5x - 27x +45
now operation on only like terms
4x²- 3x² - 3x - 8x + 5x - 27x + 5 + 45
now =
x² - 38x + 5x + 50
x² - 33x + 50
this is your answer
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