Question

4x+3y=11;3x+4y=10 solve by substituting method​

Answer 1

Answer:

x=2 & y= 1

Step-by-step explanation:

Solution :

4x+3y=11 (1)

3x+4y=10 (2)

Step 1: Adding both the equations, we get

7x+7y=21

⇒7(x+y)=7×3

⇒x+y=3 (3)

Step 2: Subtracting the equation (2) from the equation (1)

(4x+3y)−(3x+4y)=11−10

⇒x−y=1 (4)

Step 3: Adding the equations (3) and (4), we get

(x+y)+(x−y)=3+1

2x=4⇒x=2

2+y=3 (from (3))

y=1

Substituting y=1 in any of the equations (1), (2), (3) or (4), we get x=2.

The solution of the pair of equations is x=2andy=1.

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Answer 2

Answer:

The required value of x and y is 2 and 1 respectively.

Step-by-step explanation:

Here,

4x + 3y = 11 [equation (1)]

3x + 4y = 10 [equation (2)]

From [equation (1)]

4x = 11 - 3y

or, x = (11-3y)/4 [equation (3)]

substituting the value of x from [equation (3)] to [equation (2)],

3[(11-3y)/4] + 4y = 10

or, (33 - 9y)/4 + 4y = 10

or, (33 - 9y + 16y) = 40

or, 7y = 40 - 33

or, y = 7/7

Therefore, y = 1

From [equation (3),

x = (11 - 3×1)/4

or, x = 8/4

Therefore, x = 2

Hence,

x = 2 and

y = 1