Question

4x+3y=12;3x+4y=8 solve the simulation​

Answer 1

Answer:

x=2;y=1/2

Step-by-step explanation:

GIVEN:

4x+3y=12

3x+4y=8

TO FIND:

X AND Y

SOLUTION

so here we can use the method called elimination method

let ,4x+3y=12  be the first equation

3x+4y=8 be the second equation

4x+3y=12......................1

3x+4y=8 ..........................2

let us multiply the first equation with 4 and second equation with 3

ie)    16x+12y=48

       9x+12y=24......4

      (-)   (-)     (-)

________________

      7x+0y=14

ie  7x=14

      x=2

substitute x=2 in equation 4

9x+12y=24

9(2)+12Y=24

18+12y=24

12y=6

y=1/2

PLS MARK AS BRAINLIEST

Answer 2

Answer:

$x=\frac{24}{7} \ \text{and}\ y=\frac{-4}{7}$

Step-by-step explanation:

Given Equations :

$\\4x+3y=12 \ \ \ \ \ \ \ \ \ \text{equation(1)}\\3x+4y=8 \ \ \ \ \ \ \ \ \ \ \ \text{equation(2)}$

extract the value of 'y' in the form of 'x' from equation ( 2 ).

$\begin{equation*}4x+3y=12\\3y=12-4x\\y=\frac{12-4x}{3}\end{equation*}$

substitute the value of y in the second equation

$3x+4\cdot\frac{12-4x}{3}=8\\9x+48-16x=24\\-7x=24-48\\x=\frac{24}{7}$

substitute the value of x in the equation (1)

$4\cdot\frac{24}{7}+3y=12\\96+21y=84\\21y=84-96$

$21y=-12\\y=\frac{-12}{21}\\y=\frac{-4}{7}$

Hence we get   $x=\frac{24}{7} \ \text{and}\ y=\frac{-4}{7}$

#SPJ2