Question

4x+3y=12 और 2x+5x=0
समीकरणा के दो हल ज्ञात कीजिये​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

4x+3y=12 , 2x+5x=0

MULTPLYING EQ. 2ND BY 2

THEREFORE:- 4x + 10y=0

Subtracting eq. 2 from 1 we get

4x + 3y = 12

-

4x + 10y = 0

_____________

0 + 13x = 12

x = 12

13 ( First answer)

replacing the value of x in eq 1.

we get, 4(12) + 3y = 12

13

now, 3y = 12×13

48

y = 13

14( second answer)