Question

4x+3y=15,3x+4y=41, X+Yकीमत काडाहे गणित सांगा ​

Answer 1

Step-by-step explanation:

• 4x+3y=15,3x+4y=41
• 4x+3y=15
• 4x=-3y+15
• $\tt \: x=\dfrac{1}{4}\left(-3y+15\right)$
• $\tt \: x=-\dfrac{3}{4}y+\dfrac{15}{4}$
• $\tt3\left(-\dfrac{3}{4}y+\dfrac{15}{4}\right)+4y=41$
• $\tt-\dfrac{9}{4}y+\dfrac{45}{4}+4y=41$
• $\tt\dfrac{7}{4}y+\dfrac{45}{4}=41$
• $\tt\dfrac{7}{4}y=\dfrac{119}{4}$
• $\boxed{ \tt \: y = 17}$
• $\tt \: x=-\dfrac{3}{4}\times 17+\dfrac{15}{4}$
• $\tt \: x=\dfrac{-51+15}{4}$
• $\boxed{ \tt \: x=-9}$
• $\text{hence} \: \: \tt x + y = - 9 + 17 \boxed{ \red{= 8}}$