Math, asked by sadhansingha74, 8 months ago

4x-3y = 16, 6х + 5y =62​

Answers

Answered by nikithavadlamudi457
3

step by step explanation

4x-3y=16 -------1

6x+5y=62----------2

from equation 1

4x-3y=16

4x=16+3y

x=(16+3y)÷4

substitute the value of x in 2

6х+5y=62

6(16+3y)÷4+5y=623

(16+3y)÷2+5y=62

(48+9y)÷2+5y=62

(48+9y+10y)÷2=62

48+19y=2×62

19y=124-48

y=76÷19

y=4

substitute value of y in equation 1 or 2 here iam taking 1

4x-3y=16

4x-3(4)=16(as y=4)

4x-12=16

4x=16+12

4x=28

x=28÷4

x=7

x=7

y=4

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