4x + 3y = 20 , 3x/4 - y/4 = 1 Simultaneous Linear equation can someone help me?
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Answer:
x=2
y=4
Step-by-step explanation:
4x+3y=20.....eq.1
3x/4 - y/4=1
can be written as,
3x-y=4.....eq.2
multiplying eq.2 by 3 and adding it with eq.1 we get,
16x=32
therefore,
x=2
substituting x=2 in equation 1,
4(2)+3y=20
8+3y=20
3y=12
y=4
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