4x + 3y - 4 = 0 ; 6x = 8 - 5y
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4x + 3y = 0 .............. 1)
6x +5y = 8 .............. 2)
multiplying equation 1) by 5 and
multiplying equation 2) by 3 .
so we get,
20x + 15y = 0 ............... 3)
18 x + 15 y = 24 .............. 4)
now, subtract eq. 3) from eq. 4)
after subtracting... we get,
-2x = 24
therefore, x = -12
now we will substitute x= -12 in eq 1)
4 × (-12) +3y =0
-48 +3y = 0
3y = 48
y = 48 /3
y = 16
therefore we get x= -12 and y = 16.
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