Question

4x+3y-4=0 ; 6x=8-5y Solve this equations by Cramer’s method.

Answer 1

Given, 4x + 3y - 4 = 0 -------(1)
6x = 8 - 5y
6x + 5y - 8 = 0 -------(2)

use Cramer's rule ,
4x + 3y - 4 = 0
6x + 5y - 8 = 0
for equations ,
$\frac{x}{3\times-8-(-4)\times5}=\frac{-y}{4\times - 8-(-4)\times6}=\frac{1}{4\times5-3\times6}$

=> x/(-24 + 20) = -y/(-32+ 24) = 1/(20 - 18)

=> x/-4 = -y/-8= 1/2

=> x/-4 = y/8 = 1/2

=> x = -4/2 = -2 and y = 8/2 = 4

hence, x = -2 and y = 4

Answer 2

SOLUTION IS IN THE ATTACHMENT..

Determinant method (Cramer’s Rule) :
In Cramer’s method, the equations are written as a1x + b1y = c1 & a2x + b2y = c2.

The value of determinant :
D = |a1 b1|
       |a2 b2|

D = a1b2 - a2b1

Dx = |c1 b1|
         |c2 b2|

Dx = c1b2 - c2b1

Dy = |a1 c1|
         |a2 c2|

Dy = a1c2 - a2c1

We find the value of x & y by using this formula:
x = Dx / D & y = Dy / D

HOPE THIS WILL HELP YOU…