4x+3y=47,2x+5y=21
find x and y
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Answer:
4x+3y= 47 eq.(1)
2x+5y= 21 eq.(2)
from eq.2 we find
2x +5y=21
so value of 2x we put in eq.1
2*2x+3y =47
so put the value
2*(-5y+21)+3y= 47
-10y+42+3y =47
-7y =47-42
-7y =5
y =-5/7
thus we put the value of y in eq.1
so 4x+3y= 47
4x+3(-5/7)= 47
4x-15/7= 47
4x =47+15/7
4x= (47*7+15)/7
x =344/7*4
x =86/7
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