4x+3y=50 ;4x-5y=2 find x and y
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4x+3y=50......(1).
& 4x-5y=2.....(2).
Substract equation (1) with equation (2).
4x+3y=50.
-4x- 5y= 2.
8y=48.
8y=48.
y=48/8.
y=6.
By putting y value in equation (1).
4x+3y=50.
4x+3(6)=50.
4x+18=50.
4x=50-18.
4x=32.
x=32/4.
x=8.
So, x=8 & y=6.
I think this is your answer.
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