4x-3y-6=0 and x+3y=9
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Answered by
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4x-3y=6
x+3y=9
5x= 15
x=3
&
3y= (9-3)
y=2
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x+3y=9
5x= 15
x=3
&
3y= (9-3)
y=2
☺️☺️☺️☺️☺️☺️☺️☺️☺️☺️☺️☺️☺️☺️☺️
Answered by
0
Simply add both the equations:
4x-3y=6 eq. 1
+ x+3y=9 eq. 2
= 5x=15
Therefore x=3
substituting val. of x in eq. 2 we get,
(3)+3y=9
3y=6
y=2
4x-3y=6 eq. 1
+ x+3y=9 eq. 2
= 5x=15
Therefore x=3
substituting val. of x in eq. 2 we get,
(3)+3y=9
3y=6
y=2
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