Question

4x-3y-8=0 , 6x-y-29÷3=0 by substitution method​

Answer 1

Step-by-step explanation:

Given -

4x - 3y = 8

6x - y = 29/3

To Find -

Value of x and y

By Substitution method :-

4x - 3y = 8

• » y = 4x - 8/3

Substituting the value of y on 6x - y = 29/3, we get :

» 6x - (4x - 8/3) = 29/3

» 6x - 4x + 8/3 = 29/3

» 18x - 4x + 8/3 = 29/3

» 14x + 8 = 29

» 14x = 21

» x = 21/14

• » x = 3/2

And

Substituting the value of x on 4x - 3y = 8, we get :

» 4(3/2) - 3y = 8

» 6 - 3y = 8

» 6 - 8 = 3y

» -2 = 3y

• » y = -2/3

Hence,

The value of x is 3/2 and y is -2/3

Verification :-

• 4x - 3y = 8

» 4(3/2) - 3(-2/3) = 8

» 6 + 2 = 8

» 8 = 8

LHS = RHS

And

• 6x - y = 29/3

» 6(3/2) - (-2/3) = 29/3

» 9 + 2/3 = 29/3

» 27 + 2/3 = 29/3

» 29/3 = 29/3

LHS = RHS

Hence,

Verified..

Answer 2

Answer :

The values are :

x = 3/2

y = -2/3

Given :

The equations are :

• 4x - 3y - 8 = 0
• 6x - y - 29/3 = 0

To Find :

• The values of x and y

Solution :

Considering the equations :

$\sf4x - 3y - 8 = 0 \: \: ..........(1)$

and

$\sf 6x - y - \dfrac{29}{3} = 0 \\ \\ \implies \sf{y = 6x - \dfrac{29}{3} \: ............(2)}$

Putting the value of (2) in (1) we have :

$\sf \implies 4x - 3(6x - \dfrac{29}{3} ) - 8 = 0 \\ \\ \sf \implies4x - 18x + 29 - 8 = 0 \\ \\ \sf \implies - 14x + 21 = 0 \\ \\ \sf \implies - 14x = - 21 \\ \\ \sf \implies x = \dfrac{21}{14} \\ \\ \implies \bf x = \frac{3}{2}$

Now putting the value of x in (2)

$\sf \implies y = 6 \times ( \dfrac{3}{2} ) - \dfrac{29}{3} \\ \\ \sf \implies y = \frac{18}{2} - \frac{29}{3} \\ \\ \sf \implies y = 9 - \dfrac{29}{3} \\ \\ \sf \implies y = \frac{27 - 29}{3} \\ \\ \bf \implies y = - \dfrac{ 2}{3}$

Thus x = 3/2 and y = -2/3