Question

4x-3y=8 and 18x-3y=29
Find x and y by Substituting method.​

Answer 1

The given system of equation is: 4x - 3y = 8 ……(i) 6x - y = 29/ 3 ……(ii) On multiplying (ii) by 3, we get: 18x – 3y = 29 ….(iii) On subtracting (iii) from (i) we get: -14x = -21 x = 21/14 = 3/2 Now, substituting the value of x = 3/2 in (i), we get: 4 × 3/2 – 3y = 8 ⇒6 – 3y = 8 ⇒3y = 6 – 8 = -2 y = −2/ 3 Hence, the solution x = 3/2 and y = −2/3 .Read more on Sarthaks.com - https://www.sarthaks.com/129916/solve-for-x-and-y-4x-3y-8-6x-y-29-3

Answer 2

Answer:

The given system of equation is:

4x - 3y = 8 ……(i)

6x - y = 29/ 3 ……(ii)

On multiplying (ii) by 3,

we get: 18x – 3y = 29 ….(iii)

On subtracting (iii) from (i)

we get: -14x = -21 x = 21/14 = 3/2

Now, substituting the value of x = 3/2 in (i),

we get: 4 × 3/2 – 3y = 8

⇒6 – 3y = 8

⇒3y = 6 – 8 = -2 y = −2/ 3

Hence,

the solution x = 3/2 and y = −2/3