Question

4x+3y+9=0 into its normal form and find the value of P​

Answer 1

Answer:

$4x + 3x + 9 \: equle \: to \: 0 \: \\ answer \: is16 \: is \: answer$

Answer 2

ANSWER :-

p = -9/5

EXPLANATION :-

4x + 3y + 9 = 0

4x + 3y = -9

compare with ax + by = -c

a = 4 , b = 3 , c =9

divide by √ a^2 + b^2

√ 16 + 9 = √ 25 = 5

4x/5 + 3y/5 = -9/5

Compare with x cosA + y sinA = p

cosA = 4/5 , sinA = 3/5 , p = -9/5

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