Question

(4x-3y)cube square + (4x+3y)cube square

Simplify​

Answer 1

Answer:

$(a−b)3=a3−b3−3ab(a−b)$

$⟹ (a−b)3=a3−b3−3a2b+3ab2.$

$Then,$

$(4x−3y)3   </p><p></p><p>$

$=(4x)3−(3y)3 −3(4x)2(3y) +3(4x)(3y)2tex]</p><p>[tex]=64x3−144x2y+108xy2−27y3.$

Answer 2

Answer:

8x(16x² + 27y²

Step-by-step explanation: