4x^4+1+3x^3+2x by x^2+2+x
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Answer:
Here, p(x)=4x
4
−3x
3
−3x
2
+x−7, and the zero of 1−2x is
2
1
So, p(
2
1
)=4(
2
1
)
4
−3(
2
1
)
3
−3(
2
1
)
2
+(
2
1
)−7
=
4
1
−
8
3
−
4
3
+
2
1
−7
=
8
2−3−6+4−56
=−
8
59
So, by the Remainder Theorem −
8
59
is the remainder when 4x
4
−3x
3
−3x
2
+x−7 is divided by 1−2x.
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