Math, asked by nareshshah, 1 year ago

4x^4+2x^3-px-28 has -2 as its zero find the value of p for which the polunomial

Answers

Answered by prathamchauhan4

p(-2)=4(-2)^4+2(-2)^3-p(-2)-28
=56-16-2p-28
=12-2p
As p(x) is the factor of f(x)

12-2p=0
-2p= -12
p= -12/-2
p=6

nareshshah: thanks

welcomearunagap3qhb1: wrong

welcomearunagap3qhb1: 4*(-2)^4 is 4*16=64

Answered by welcomearunagap3qhb1

p(-2)=4(-2)^4 +2(-2)^3-p(-2) -28=0
4*16+2*(-8)-px-28=0
64-16-px-28=0
20-px=0
20-p(-2)=0
20+2p=0
20=-2p
p=-20/2
p=-10
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nareshshah: thanks bro

welcomearunagap3qhb1: welcome

welcomearunagap3qhb1: can u mark me brainliest

welcomearunagap3qhb1: its not compelling but if u want

welcomearunagap3qhb1: hello............thats wrong answer and im confident of mine

welcomearunagap3qhb1: check properly

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