Question

4x^4-37x^2+9=0 quadratic equation. please solve and give answer, it's urgent​

Answer 1

Answer:

$x = \frac{1}{2} \: \: \: \: \: \: \: \: x = - \frac{1}{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = 3 \: \: \: \: \: \: \: \: \: \: \: x = - 3$

Step-by-step explanation:

$4 {x}^{4} - 37 {x}^{2} + 9 = 0 \\ \\ 4 {x}^{4} - 36 {x}^{2} - {x}^{2} + 9 = 0 \\ \\ 4 { {x}^{2} ( {x}^{2} - 9) }^{} - 1( {x}^{2} - 9) = 0 \\ \\ (4 {x}^{2} - 1)( {x}^{2} - 9) = 0 \\ \\ 4 {x}^{2} = 1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: {x}^{2} = 9 \\ \\ x = \frac{1}{2} \: \: \: \: \: \: \: \: x = - \frac{1}{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = 3 \: \: \: \: \: \: \: \: \: \: \: x = - 3$