(4x^4-5x^3-7x+1)÷(4x-1)
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4x⁴–5x³–7x+1) ÷ (4x–1)
=> \frac{4 {x}^{4} - 5 {x}^{3} - 7x + 1 }{4x - 1} \\ \\
= > {x}^{3} - {x}^{2} - \frac{1}{4} x - \frac{29}{16} = Quotient \: and \: (- \frac{13}{16} )= Remainder
i hope u understand
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