4x^4 + 7x^2 - 2
Factorie it PLEASE
Answers
Answered by
1
Step-by-step explanation:
LET X^2 BE A
4A^2+7A-2
4A^2-A+8A-2
A(4A-1)+2(4A-1)
(4A-1)(A+2)
PUTTING THE VALUE OF A
(4×X^2 -1)(X^2+2)
(4X^2-1)(X^2+2)
((2X)^2-(1)^2) (X^2+2)
(2X+1)(2X-1)(X^2+2)
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Answered by
2
Let x² =p, then the equation 4x⁴ +7x² −2
becomes 4p² +7p−2
Consider the expression 4p² +7p−2 and factorise it as follows:
4p² +7p−2= 4p² +8p−p−2=4p(p+2)−1(p+2)
=(4p−1) (p+2)
Now, substitute the value of p as p=x²:
(4p−1)(p+2) = (4x²−1)(x²+2) = (2x+1) (2x−1) (x² +2)
(Using identity a² −b² = (a+b) (a−b)
Hence, 4x⁴ +7x²−2
= (2x+1) (2x−1) (x² +2)
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