Question

(4x+4)-(7x-8)/4x-5=-4/3

Answer 1

may be you can solve the equation.

Answer 2

Answer:

${\large{\bold{\rm{\underline{Required \; Solution}}}}}$

Question -

${\sf{\dfrac{(4 x \times 4) - (7 x - 8)}{4x + 5} = - \dfrac{4}{3}}}$

Solution -

$\; \; \; \; \; \; \; \;{\bf{\rightarrow \dfrac{(4x \times 4) - (7x -8)}{4x + 5} = \dfrac{-4}{3}}}$

Let us multiply and let's use rule of linear equation in one variable.

$\; \; \; \; \; \; \; \;{\bf{\rightarrow \dfrac{16x -7x + 8}{4x + 5} = \dfrac{-4}{3}}}$

Now let us cross multiply the digits.

$\; \; \; \; \; \; \; \;{\bf{\rightarrow (9x+8)(3) = (-4)(4x+5)}}$

Now let's multiply.

➝ 9x × 3

➝ 8 × 3

➝ -4 × 4

➝ -4 × 5

$\; \; \; \; \; \; \; \;{\bf{\rightarrow 27x + 24 = -16x -20}}$

Now let's combine like terms or again let's use rule of linear equation in one variable.

$\; \; \; \; \; \; \; \;{\bf{\rightarrow 27x + 16x = -20 - 20}}$

Now let's add or subtract

$\; \; \; \; \; \; \; \;{\bf{\rightarrow 43x = -44}}$

Again let's use rule of linear equation in one variable.

$\; \; \; \; \; \; \; \;{\bf{\rightarrow x = \dfrac{-44}{43}}}$

${\Large{\bf{\boxed{\dfrac{-44}{43}}}}}$

hope it's helpful