Question

(4x+4)-(7x-8)/4x+5=-4/3
Please solve quickly

Answer 1

Answer:

We move all terms to the left:

(4x+4)-(7x-8)/4x-5-(4/3)=0

Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R

We add all the numbers together, and all the variables

(4x+4)-(7x-8)/4x-5-(+4/3)=0

We get rid of parentheses

4x-(7x-8)/4x+4-5-4/3=0

We calculate fractions

4x+(-21x+24)/12x+(-16x)/12x+4-5=0

We add all the numbers together, and all the variables

4x+(-21x+24)/12x+(-16x)/12x-1=0

We multiply all the terms by the denominator

4x*12x+(-21x+24)+(-16x)-1*12x=0

Wy multiply elements

48x^2+(-21x+24)+(-16x)-12x=0

We get rid of parentheses

48x^2-21x-16x-12x+24=0

We add all the numbers together, and all the variables

48x^2-49x+24=0

a = 48; b = -49; c = +24;

Δ = b2-4ac

Δ = -492-4·48·24

Δ = -2207