Math, asked by shukladivyansh073, 2 days ago

4x - 4^x - 1 = 24, Find (2x)^x

Answers

Answered by ITXNOBITA
4

(4^x) - (4^(x-1)) = 24

(4^(x-1)) [ 4 - 1 ] = 24

4^(x-1) = 8

(x-1) log4 = log8

x = 1 + (log 8 / log4 )

x = 2.5

(2x) ^ x = 5^2.5 = 25√5

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Answered by py170686
1

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