Question

4x^-4ax+a^-b^=0 Do it by quadratic equation

Answer 1

4x^2-4ax+(a^2-b^2)=0

=> (4x^2-4ax+a^2)-b^2=0

=>(2x-a)^2-b^2=0

=>{2x-a-b}{2x-a+b}=0

=> x=(a+b)/2 , (a-b)/2