Question

4x^5+2x^4-x^3+4x^2-7 divided by (x-1) by long division method

Answer 1

GIVEN :

The expression is $4x^5+2x^4-x^3+4x^2-7$ divided by (x-1) by long division method

TO FIND :

The quotient and remainder for the given expression $4x^5+2x^4-x^3+4x^2-7$ divided by (x-1) by long division method

SOLUTION :

Given that the expression $4x^5+2x^4-x^3+4x^2-7$ divided by (x-1) by long division method

Given expression can be written as $4x^5+2x^4-x^3+4x^2+0x-7$

         $4x^4+6x^3+5x^2+9x+9$

    ______________________________

x-1) $4x^5+2x^4-x^3+4x^2+0x-7$

      $4x^5-4x^4$

    _(-)___(+)_______________

                   $6x^4-x^3$

                   $6x^4-6x^3$

                 _(-)___(+)_____________

                              $5x^3+4x^2$

                              $5x^3-5x^2$

                         __(-)___(+)____________

                                          $9x^2+0x$

                                          $9x^2-9x$

                                         _(-)__(+)______

                                                     9x-7

                                                     9x-9

                                                   _(-)_(+)_

                                                            2

                                                    ______

The quotient $4x^4+6x^3+5x^2+9x+9$  is and remainder is 2 when the given expression $4x^5+2x^4-x^3+4x^2-7$ is divided by (x-1) by long division method.

∴ $Quotient=4x^4+6x^3+5x^2+9x+9$ and remainder=2.

Answer 2

Answer:

refer to the attachment

Step-by-step explanation:

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