(4x-5) (4x-1) by using identity
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Answer:
x²+(a+b)x+ab identity will be used
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(4x-5)(4x-1)
(x+a)(x+b)=x²+(a+b)x+ab
x=4x;a=-5;b=-1
(4x)²+(-5+(-1))4x+(-5)(-1)
16x²-5-1*4x-5*(-1)
16x²-24x+5
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