(4x - 5) (4x - 1) find this by using identity (x+a)(x+b)
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(x+a)(x+b) = x²+bx+ax+ab = x²+(a+b)x+ab
Comparing (4x-5)(4x-1) with (x+a)(x+b) we get,
x = 4x, a = -5, b = -1
Therefore,(4x-5)(4x-1)
= (4x)²+(-5-1)(4x)+(-5)(-1)
= 16x²+(-6)(4x)+5
= 16x²-24x+5
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